AP EAMCET · Chemistry · Ionic Equilibrium
The percentage of ionization of 1 L of \(x \mathrm{M}\) acetic acid is 4.242 and is called solution "A". The percentage of ionization of 1 L of \(y \mathrm{M}\) acetic acid is 3 and is called solution "B". Solution "A" is mixed with solution "B". What is the concentration of acetic acid in the resultant solution?
\(\left(\mathrm{K}_{\mathrm{a}} \text { of acetic acid }=1.8 \times 10^{-5}\right)\)
- A 0.05 M
- B 0.015 M
- C 0.02 M
- D 0.15 M
Answer & Solution
Correct Answer
(B) 0.015 M
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