AP EAMCET · Maths · Circle
If the lines \(3 x-4 y+4=0\) and \(6 x-8 y-7=0\) are the tangents to the same circle, then the area of that circle (in sq.units) is
- A \(\frac{3 \pi}{4}\)
- B \(\frac{16 \pi}{25}\)
- C \(\frac{9 \pi}{4}\)
- D \(\frac{9 \pi}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{9 \pi}{16}\)
Step-by-step Solution
Detailed explanation
\(d = \frac{|C_1 - C_2|}{\sqrt{A^2 + B^2}}\) for lines \(3x - 4y + 4 = 0\) and \(3x - 4y - \frac{7}{2} = 0\) \(d = \frac{|4 - (-\frac{7}{2})|}{\sqrt{3^2 + (-4)^2}} = \frac{|\frac{8+7}{2}|}{\sqrt{9+16}} = \frac{\frac{15}{2}}{5} = \frac{3}{2}\)…
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