AP EAMCET · Maths · Quadratic Equation
If \(\frac{x^2+x+1}{x^2+2 x+1}=A+\frac{B}{x+1}+\frac{C}{(x+1)^2}\), then \(A-B\) is equal to
- A \(4 C\)
- B \(4 C+1\)
- C \(3 C\)
- D \(2 C\)
Answer & Solution
Correct Answer
(D) \(2 C\)
Step-by-step Solution
Detailed explanation
\[ \frac{x^2+x+1}{x^2+2 x+1}=1-\frac{x}{x^2+2 x+1} \] Now, \(\frac{x}{x^2+2 x+1}=\frac{A}{(x+1)}+\frac{B}{(x+1)^2}\) \[ \Rightarrow \quad x=A(x+1)+B \] On equating the coefficient of \(x\) and constant, we get…
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