AP EAMCET · Maths · Indefinite Integration
If \(\frac{x}{\left(1+x^2\right)(3-2 x)}=\frac{B x+C}{1+x^2}+\frac{A}{3-2 x}\), then \(C\) is
- A \(\frac{2}{3}\)
- B \(\frac{1}{13}\)
- C \(\frac{-1}{13}\)
- D \(\frac{-2}{13}\)v
Answer & Solution
Correct Answer
(D) \(\frac{-2}{13}\)v
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