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AP EAMCET · Maths · Pair of Lines

If two sides of a triangle are represented by \(3 x^2-5 x y+2 y^2=0\) and its orthocentre is \((2,1)\), then the equation of the third side is

  1. A \(2 x+y-4=0\)
  2. B \(6 x+3 y-13=0\)
  3. C \(8 x+4 y-17=0\)
  4. D \(10 x+5 y-21=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(10 x+5 y-21=0\)

Step-by-step Solution

Detailed explanation

\((3x-2y)(x-y)=0 \implies 3x-2y=0, x-y=0\). Vertex A is \((0,0)\). \(m_{AH} = \frac{1-0}{2-0} = \frac{1}{2}\). \(m_{BC} = -2\). Altitude from B to \(x-y=0\): \(y-1 = -1(x-2) \implies x+y=3\). Vertex B is intersection of \(3x-2y=0\) and \(x+y=3\):…