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AP EAMCET · Maths · Functions

If \(f: R \rightarrow R\) is defined by
\(f(x)= \begin{cases}|[x-5]|, & \text { for } x < 5 \\ {[|x-5|],} & \text { for } x \geq 5\end{cases}\)
Then, \((f \circ f)\left(-\frac{7}{2}\right)=\)
(here, \([x]\) is the greatest integer not exceeding \(x\))

  1. A \((f \circ f)\left(-\frac{11}{2}\right)\)
  2. B \((f \circ f)\left(-\frac{9}{2}\right)\)
  3. C \((f \circ f)(3)\)
  4. D \((f \circ f)\left(\frac{9}{2}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((f \circ f)\left(\frac{9}{2}\right)\)

Step-by-step Solution

Detailed explanation

\(f \circ f\left(-\frac{7}{2}\right)=f\left[\left[-\frac{7}{2}-5\right]=f(9)=|[19-51]|=4\right.\) By checking option (A) \(\rightarrow f\left(\mid\left[-\frac{11}{2}-5\right]\right)=6\) (B) \(\longrightarrow f \circ f\left(-\frac{9}{2}\right)=5\) (C) \(\rightarrow f o f(3)=3\)…