AP EAMCET · Maths · Vector Algebra
Let \(A B C D E F\) be a regular hexagon with the vertices \(A, B, C, D, E, F\) counterclock-wise. Then the vector \(\mathbf{A B}+\mathbf{A F}+\mathbf{C D}+\mathbf{E F}\) is equal to
- A \(\mathrm{DE}+\mathrm{FA}\)
- B \(\mathrm{CB}+\mathrm{ED}\)
- C \(\mathrm{BC}+\mathrm{FA}\)
- D \(\mathrm{BC}+\mathrm{DE}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{BC}+\mathrm{DE}\)
Step-by-step Solution
Detailed explanation
In a regular hexagon \(A B C D E F\), We know that, \(\mathbf{A B}+\mathbf{B C}+\mathbf{C D}=\mathbf{A D}=2 \mathbf{B C}\)…
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