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AP EAMCET · Maths · Ellipse

If the tangent at the point \((1,2)\) on the ellipse \(3 x^2+4 y^2=19\) is also a tangent to the parabola \(y^2-k x=0\), then \(k=\)

  1. A \(\frac{57}{16}\)
  2. B \(\frac{-57}{64}\)
  3. C \(\frac{57}{64}\)
  4. D \(\frac{-57}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{-57}{16}\)

Step-by-step Solution

Detailed explanation

Equation of tangent at the point \((1,2)\) on the ellipse \(3 x^2+4 y^2=19\) is \[ 3 \cdot x \cdot 1+4 \cdot y \cdot 2=19 \] This is also tangent to the parabola From Eqs. (i) and (ii), we get \[ y^2-k\left(\frac{19-8 y}{3}\right)=0 \]…
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