AP EAMCET · Maths · Quadratic Equation
If the roots of the equation \(x^3-a x^2+b x-c=0\) are in GP, then \(\frac{b^3}{a^3}\)
- A 1
- B –1
- C \(\mathrm{c}\)
- D \(-c\)
Answer & Solution
Correct Answer
(C) \(\mathrm{c}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \text { Let roots be } \frac{p}{r}, p, p r \\ & \therefore \quad \frac{p}{r}+P+p r=a \\ & \frac{p^2}{r}+P^2 r+p^2=b \end{aligned} \] \[ p^3=c \]…
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