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AP EAMCET · Maths · Quadratic Equation

If the roots of the equation \(x^3-13 x^2+\mathrm{K} x-27=0\) are in geometric progression then \(\mathrm{K}=\)

  1. A \(-30\)
  2. B \(30\)
  3. C \(39\)
  4. D \(-39\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(39\)

Step-by-step Solution

Detailed explanation

Given the equation, \(x^3-13 x^2+K x-27=0\) Let roots are \(\frac{a}{r}, a, a r\) Now, \(\frac{a}{r} \cdot a \cdot a r=\frac{-(-27)}{1} \Rightarrow a^3=27 \Rightarrow a=3\) and, \(\frac{3}{r}+3+3 r=\frac{-(-13)}{1} \Rightarrow \frac{3}{r}+3 r=10 \Rightarrow r=3, \frac{1}{3}\)…