AP EAMCET · Maths · Properties of Triangles
If the area of triangle \(A B C\) is \(b^2-(c-a)^2\), then \(\tan B=\)
- A 1
- B \(\frac{13}{15}\)
- C \(\frac{1}{4}\)
- D \(\frac{8}{15}\)
Answer & Solution
Correct Answer
(D) \(\frac{8}{15}\)
Step-by-step Solution
Detailed explanation
Given, \(\begin{aligned} & \text { Area of a triangle }=b^2-(c-a)^2 \\ \Delta & =b^2-(c-a)^2 \\ & =(b+c-a)(b-c+a) \\ & =(2 s-2 a)(2 s-2 c) \\ & =4(s-a)(s-c) \end{aligned}\) Now \(\sqrt{s(s-a)(s-b)(s-c)}=4(s-a)(s-c)\)…
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