AP EAMCET · Maths · Circle
If the point \((2, \lambda)\) lies inside the circles \(x^2+y^2=13\) and \(x^2+y^2+x-2 y=14, \lambda\) lies in the set
- A \((-\infty,-3) \cup(4, \infty)\)
- B \((-\infty,-1) \cup(3, \infty)\)
- C \([-3,4]\)
- D \((-2,3)\)
Answer & Solution
Correct Answer
(D) \((-2,3)\)
Step-by-step Solution
Detailed explanation
Given, \(S_1 \equiv x^2+y^2-13, S_2 \equiv x^2+y^2+x-2 y-14\) According to question, \(S_1(2, \lambda) \(\therefore \quad \lambda \in(-2,3)\)
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