AP EAMCET · Maths · Pair of Lines
If the pairs of straight lines represented by \(3 x^2+2 h x y-3 y^2=0\) and \(3 x^2+2 h x y-3 y^2+2 x-4 y+c=0\) form a square, then \((h, c)=\)
- A \((4,-1)\)
- B \((-1,4)\)
- C \((-4,1)\)
- D \((1,-4)\)
Answer & Solution
Correct Answer
(A) \((4,-1)\)
Step-by-step Solution
Detailed explanation
Given, equations of pair of straight lines both represents pair of perpendicular lines. Now, the point of intersection the lines given by \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) is \(\left(\frac{h f-b g}{a b-h^2}, \frac{g h-a f}{a b-h^2}\right)\), So for the pair of lines (ii),…
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