AP EAMCET · Maths · Parabola
If the ordinates of points \(P\) and \(Q\) on the parabola \(y^2=12 x\) are in the ratio \(1: 2\), then the locus of the point of intersection of the normals to the parabola at P and Q is
- A \(y+18\left(\frac{x-6}{21}\right)^{3 / 2}=0\)
- B \(y-18\left(\frac{x-6}{12}\right)^{3 / 2}=0\)
- C \(y+12\left(\frac{x-6}{14}\right)^{1 / 2}=0\)
- D \(y-12\left(\frac{x-6}{18}\right)^{3 / 2}=0\)
Answer & Solution
Correct Answer
(A) \(y+18\left(\frac{x-6}{21}\right)^{3 / 2}=0\)
Step-by-step Solution
Detailed explanation
Given, \(\frac{t_1}{t_2}=2\) Let \(t_2=t \Rightarrow t_1=2 t\) Point of intersection of normals at \(t_1\) and \(t_2\) is…
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