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AP EAMCET · Maths · Straight Lines

If the median AD of the triangle ABC is bisected at E and BE meets AC in F, then \(\mathrm{AF}: \mathrm{AC}=\)

  1. A \(1: 4\)
  2. B \(1: 3\)
  3. C \(1: 2\)
  4. D \(3: 4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1: 3\)

Step-by-step Solution

Detailed explanation

Apply Menelaus' Theorem to \(\triangle ADC\) and transversal \(\overline{BFE}\): \(\frac{AF}{FC} \cdot \frac{CB}{BD} \cdot \frac{DE}{EA} = 1\) Substitute known ratios (\(D\) is midpoint of \(BC \implies \frac{CB}{BD} = 2\); \(E\) is midpoint of…