AP EAMCET · Maths · Straight Lines
If the lines \(3 x+y-4=0, x-\alpha y+10=0, \beta x+2 y+4=\) 0 and \(3 x+y+k=0\) represent the sides of a square, then \(\alpha \beta(k+4)^2=\)
- A \(-256\)
- B \(-512\)
- C \(-128\)
- D \(-1024\)
Answer & Solution
Correct Answer
(B) \(-512\)
Step-by-step Solution
Detailed explanation
Since, \(m_{\mathrm{AB}}=-3, m_{\mathrm{BC}}=\frac{1}{\alpha}\) \(\because m_{\mathrm{AB}} \cdot m_{\mathrm{BC}}=-1 \Rightarrow \frac{-3}{\alpha}=-1 \Rightarrow \alpha=3\)…
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