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AP EAMCET · Maths · Trigonometric Equations

If the general solution of \(\sin 5 x=\cos 2 x\) is of the form \(a_n \cdot \frac{\pi}{2}\) for \(n=0, \pm 1, \pm 2, \ldots .\). , then \(a_n=\)

  1. A \(\frac{2 n}{5+2(-1)^n}\)
  2. B \(\frac{2 n+(-1)^n}{5+2(-1)^n}\)
  3. C \(\frac{2 n+1}{5+2(-1)^n}\)
  4. D \(\frac{2 n-1}{5+2(-1)^n}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{2 n+(-1)^n}{5+2(-1)^n}\)

Step-by-step Solution

Detailed explanation

Given, \[ \Rightarrow \quad \begin{aligned} & \sin 5 x=\cos 2 x \\ & \quad \sin 5 x=\sin \left(\frac{\pi}{2}-2 x\right) \end{aligned} \]…