AP EAMCET · Maths · Trigonometric Equations
If the general solution of \(\sin 5 x=\cos 2 x\) is of the form \(a_n \cdot \frac{\pi}{2}\) for \(n=0, \pm 1, \pm 2, \ldots .\). , then \(a_n=\)
- A \(\frac{2 n}{5+2(-1)^n}\)
- B \(\frac{2 n+(-1)^n}{5+2(-1)^n}\)
- C \(\frac{2 n+1}{5+2(-1)^n}\)
- D \(\frac{2 n-1}{5+2(-1)^n}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 n+(-1)^n}{5+2(-1)^n}\)
Step-by-step Solution
Detailed explanation
Given, \[ \Rightarrow \quad \begin{aligned} & \sin 5 x=\cos 2 x \\ & \quad \sin 5 x=\sin \left(\frac{\pi}{2}-2 x\right) \end{aligned} \]…
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