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AP EAMCET · Maths · Circle

If the equation of the circle having its centre in the second quadrant touches the coordinate axes and also the line \(\frac{x}{5}+\frac{y}{12}=1\) is \(x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0\), then \(\lambda=\)

  1. A 3
  2. B 10
  3. C 15
  4. D -2
Verified Solution

Answer & Solution

Correct Answer

(B) 10

Step-by-step Solution

Detailed explanation

Given, equation of circle is \(x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0\)...(i) Here, centre is \((-\lambda, \lambda)\) and radius \(=\lambda\) Since, circle (i) touches \(12 x+5 y-60=0\)…