AP EAMCET · Maths · Circle
If the equation of the circle having its centre in the second quadrant touches the coordinate axes and also the line \(\frac{x}{5}+\frac{y}{12}=1\) is \(x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0\), then \(\lambda=\)
- A 3
- B 10
- C 15
- D -2
Answer & Solution
Correct Answer
(B) 10
Step-by-step Solution
Detailed explanation
Given, equation of circle is \(x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0\)...(i) Here, centre is \((-\lambda, \lambda)\) and radius \(=\lambda\) Since, circle (i) touches \(12 x+5 y-60=0\)…
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