AP EAMCET · Maths · Three Dimensional Geometry
If the direction cosines of a line satisfy the relations \(l-m+n=0\) and \(l m+m m-4 n l=0\), then the direction cosines of the line are
- A \(\left(\frac{-1}{\sqrt{6}}, \frac{2}{\sqrt{6}}, \frac{1}{\sqrt{6}}\right)\)
- B \(\left(\frac{1}{\sqrt{6}}, \frac{-2}{\sqrt{6}}, \frac{1}{\sqrt{6}}\right)\)
- C \(\left(\frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}, \frac{-1}{\sqrt{6}}\right)\)
- D \(\left(\frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}, \frac{1}{\sqrt{6}}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{1}{\sqrt{6}}, \frac{2}{\sqrt{6}}, \frac{1}{\sqrt{6}}\right)\)
Step-by-step Solution
Detailed explanation
\(\because l, m\) and \(n\) are the direction cosines of any line \(\therefore \quad l^2+m^2+n^2=1\)...(i) Given, \(l-m+n=0\)…
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