AP EAMCET · Maths · Differential Equations
If the degree of the differential equation corresponding to the family of curves \(\mathrm{y}=\mathrm{ax}+\frac{1}{\mathrm{a}}\) (where \(a \neq 0\) is an arbitary constant) is r and it's order is m, then the solution of \(\frac{d y}{d x}=\frac{y}{2 x}, y(1)=\sqrt{r+m}\) is
- A \(y=3^x\)
- B \(y^2=3 x\)
- C \(x^2=3 y\)
- D \(y=3 \log x\)
Answer & Solution
Correct Answer
(B) \(y^2=3 x\)
Step-by-step Solution
Detailed explanation
\(\frac{dy}{dx}=a\) \(y=x\left(\frac{dy}{dx}\right)+\frac{1}{\left(\frac{dy}{dx}\right)}\) \(x\left(\frac{dy}{dx}\right)^2 - y\left(\frac{dy}{dx}\right) + 1 = 0\) \(m=1, r=2\) \(y(1)=\sqrt{r+m}=\sqrt{1+2}=\sqrt{3}\) \(\frac{dy}{y}=\frac{dx}{2x}\)…
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