AP EAMCET · Maths · Sequences and Series
If the angles \(A, B\) and \(C\) of \(\triangle A B C\) are in arithmetic progression, then
- A \(b^2=a^2+c^2-a c\)
- B \(c^2=b^2+a^2-a b\)
- C \(a^2=b^2+c^2-b c\)
- D \(c^2=a^2+b^2\)
Answer & Solution
Correct Answer
(A) \(b^2=a^2+c^2-a c\)
Step-by-step Solution
Detailed explanation
The angles of \(\triangle A B C\) are in AP. \(\therefore \quad 2 B=A+C \quad\left[\because A+B+C=180^{\circ}\right]\) \(\Rightarrow \quad 2 B=180^{\circ}-B \Rightarrow B=60^{\circ}\) Now, \(\cos B=\frac{a^2+c^2-b^2}{2 a c}\)…
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