AP EAMCET · Chemistry · Ionic Equilibrium
The solubility ' \(\mathrm{S}\) ' of \(\mathrm{Zr}_3\left(\mathrm{PO}_4\right)_4\) in terms of its solubility product, \(\mathrm{K}_{\mathrm{sp}}\) is
- A \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{144}\right)^{\frac{1}{4}}\)
- B \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{6912}\right)^{\frac{1}{5}}\)
- C \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{1728}\right)^{\frac{1}{6}}\)
- D \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{6912}\right)^{\frac{1}{7}}\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{\mathrm{K}_{\mathrm{sp}}}{6912}\right)^{\frac{1}{7}}\)
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