AP EAMCET · Maths · Binomial Theorem
If \(\mathrm{P}_{\mathrm{n}}\) denotes the product of the binomial coefficients in the expansion of \((1+\mathrm{x})^{\mathrm{n}}\), then \(\frac{P_{n+1}}{P_n}=\)
- A \(\frac{\mathrm{n}+1}{\mathrm{n}!}\)
- B \(\frac{\mathrm{n}^{\mathrm{n}}}{\mathrm{n}!}\)
- C \(\frac{(\mathrm{n}+1)^{\mathrm{n}}}{(\mathrm{n}+1)!}\)
- D \(\frac{(\mathrm{n}+1)^{\mathrm{n}+1}}{(\mathrm{n}+1)!}\)
Answer & Solution
Correct Answer
(D) \(\frac{(\mathrm{n}+1)^{\mathrm{n}+1}}{(\mathrm{n}+1)!}\)
Step-by-step Solution
Detailed explanation
\( \mathrm{P}_{\mathrm{n}} = \prod_{k=0}^{n} \binom{n}{k} \) \( \mathrm{P}_{\mathrm{n+1}} = \prod_{k=0}^{n+1} \binom{n+1}{k} \) \( \frac{P_{n+1}}{P_n} = \left( \prod_{k=0}^{n} \frac{\binom{n+1}{k}}{\binom{n}{k}} \right) \cdot \binom{n+1}{n+1} \)…
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