AP EAMCET · Maths · Circle
If \(\mathrm{P}(\alpha, \beta)\) is the radical centre of the circles \(\mathrm{S} \equiv \mathrm{x}^2+\mathrm{y}^2+4 \mathrm{x}+7=0\), \(S^{\prime} \equiv 2 x^2+2 y^2+3 x+5 y+9=0\) and \(S^{\prime \prime} \equiv x^2+y^2+y=0\), then the length of the tangent drawn from \(P\) to \(S^{\prime}=0\) is
- A \(5\)
- B \(8\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{S}_1 \equiv \mathrm{x}^2+\mathrm{y}^2+4 \mathrm{x}+7=0\) \(\mathrm{S}_2 \equiv \mathrm{x}^2+\mathrm{y}^2+\frac{3}{2} \mathrm{x}+\frac{5}{2} \mathrm{y}+\frac{9}{2}=0\) \(\mathrm{S}_3 \equiv \mathrm{x}^2+\mathrm{y}^2+\mathrm{y}=0\) Radical axis (RA1):…
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