AP EAMCET · Maths · Three Dimensional Geometry
If \(\mathbf{n}=2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}\),
\(\mathbf{m}=\hat{\mathbf{i}}-\hat{\mathbf{j}}, \mathbf{l}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}\), then the Cartesian equation of the plane passing through the line of intersection of two planes \(\mathbf{r} . \mathbf{n}=1\) and \(\mathbf{r} . \mathbf{m}=-4\) and perpendicular to the plane \(\mathbf{r} \cdot \mathbf{l}=-8\) is
- A \(5 x-20 y-12 z-44=0\)
- B \(x-2 y-12 z-45=0\)
- C \(5 x-20 y-12 z-47=0\)
- D \(5 x-2 y-12 z+47=0\)
Answer & Solution
Correct Answer
(D) \(5 x-2 y-12 z+47=0\)
Step-by-step Solution
Detailed explanation
Plane passing through the line of intersection of planes \(\mathbf{r} \cdot \mathbf{n}=1\) and \(\mathbf{r} \cdot \mathbf{m}=-4\) \(\mathbf{r} \cdot(\mathbf{n}+\lambda \mathbf{m})=1-4 \lambda(\) where \(\lambda\) is a scalar quantities) This plane is \(\perp\) to the plane…
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