AP EAMCET · Maths · Definite Integration
If \(I_n=\int_0^{\pi / 4} \tan ^n \theta d \theta\) for \(n=1,2,3, \ldots\), then \(I_{n-1}+I_{n+1}\) is equal to
- A 0
- B 1
- C \(\frac{1}{n}\)
- D \(\frac{1}{n+1}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{n}\)
Step-by-step Solution
Detailed explanation
Given, \(I_n=\int_0^{\pi / 4} \tan ^n \theta d \theta\)…
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