AP EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) are the roots of \(x^2+p x+q=0\), then the values of \(\alpha^3+\beta^3\) and \(\alpha^4+\alpha^2 \beta^2+\beta^4\) are respectively ...... and ......
- A \(\left(3 p q-p^3\right)\) and \(\left(p^4-3 p^2 q+3 q^2\right)\)
- B \(-p\left(3 q-p^2\right)\) and \(\left(p^2-q\right)\left(p^2+3 q\right)\)
- C \((p q-4)\) and \(\left(p^4-q^4\right)\)
- D \(\left(3 p q-p^3\right)\) and \(\left(p^2-q\right)\left(p^2-3 q\right)\)
Answer & Solution
Correct Answer
(D) \(\left(3 p q-p^3\right)\) and \(\left(p^2-q\right)\left(p^2-3 q\right)\)
Step-by-step Solution
Detailed explanation
Since \(\alpha\) and \(\beta\) are roots of equation \[ \begin{aligned} & x^2+p x+q=0, \text { so } \\ & \alpha+\beta=-p \text { and } \alpha \beta=q \end{aligned} \] As we know that, \(\alpha^3+\beta^3=(\alpha+\beta)\left(\alpha^2+\beta^2-\alpha \beta\right)\)…
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