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AP EAMCET · Maths · Quadratic Equation

If \(\alpha, \beta\) and \(\gamma\) are the roots of equation \(5 \mathrm{x}^3-4 \mathrm{x}^2+3 \mathrm{x}-2=0\), then \(\alpha^3+\beta^3+\gamma^3=\)

  1. A \(\frac{17}{25}\)
  2. B \(\frac{394}{125}\)
  3. C \(\frac{34}{125}\)
  4. D \(\frac{34}{25}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{34}{125}\)

Step-by-step Solution

Detailed explanation

\(\sum \alpha = -\frac{-4}{5} = \frac{4}{5}\) \(\sum \alpha\beta = \frac{3}{5}\) \(\sum \alpha^2 = (\sum \alpha)^2 - 2\sum \alpha\beta = \left(\frac{4}{5}\right)^2 - 2\left(\frac{3}{5}\right) = \frac{16}{25} - \frac{6}{5} = \frac{16-30}{25} = -\frac{14}{25}\)…