AP EAMCET · Maths · Basic of Mathematics
If \(a=\frac{x}{y-z}, b=\frac{y}{z-x}\) and \(c=\frac{z}{x-y}\), where \(x, y\) and \(z\) are not all zero, then what is the value of \(a b+b c+c a=\) ?
- A 0
- B -1
- C 1
- D 2
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
We have, \(a=\frac{x}{y-z}, b=\frac{y}{z-x}, c=\frac{z}{x-y}\) where, \(x, y, z \neq 0\) Put \(x=1, y=2 \text { and } z=3\) \(\begin{aligned} & a=\frac{1}{2-3}=-1 \\ & b=\frac{2}{3-1}=1 \\ & c=\frac{3}{1-2}=-3 \end{aligned}\) Now, \(a b+b c+c a=-1-3+3=-1\)…
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