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AP EAMCET · Maths · Circle

If a foot of the normal from the point (4,3) to a circle is (2,1) and 2x-y-2=0 is a diameter of the circle, then the equation of circle is

  1. A x2+y2+2x+1=0
  2. B x2+y2+2x1=0
  3. C x2+y22x1=0
  4. D 2x2+y22x1=0
Verified Solution

Answer & Solution

Correct Answer

(C) x2+y22x1=0

Step-by-step Solution

Detailed explanation

Given, the normal from the point 4, 3 to a circle is 2, 1. So, the equation of this normal is y-1=3-14-2x-2 ⇒ y=x-1  ...1, As, the normal at any point to the circle passes through its centre. And, we have a given diameter…