AP EAMCET · Maths · Permutation Combination
If a five digit number divisible by 3 is to be formed using the numbers \(0,1,2,3,4\) and 5 without repetition, then the total number of ways this can be done is
- A 120
- B 144
- C 192
- D 216
Answer & Solution
Correct Answer
(D) 216
Step-by-step Solution
Detailed explanation
Any number is divisible by 3 if sum of its all digit is divisible by 3 . (i) Sum when digits are \(0,1,2,3,4=10\) not divisible by 3 (ii) Sum when digits are \(0,1,2,3,5=11\) not divisible by 3 (iii) Sum when digits are \(0,1,2,4,5=12\) divisible by 3 So, number of 5 digit…
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