AP EAMCET · Maths · Straight Lines
Given points, \(A(6,0), B(0,4)\) and \(O\) as the origin, find the locus of a point \(P\) such that area of \(\triangle P O B\) is 2 times the area of \(\triangle P O A\).
- A \(x^2-3 y^2=0\)
- B \(x^2+3 y^2=0\)
- C \(x^2-9 y^2=0\)
- D \(x^2-4 y^2=0\)
Answer & Solution
Correct Answer
(C) \(x^2-9 y^2=0\)
Step-by-step Solution
Detailed explanation
Given points, Let \(P\) be \((x, y)\) \(\because \quad \operatorname{ar}(\triangle P O B)=2 \cdot \operatorname{ar}(\triangle P O A)\) ...(i) Now, \(\operatorname{ar}(\triangle P O B)\)…
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