AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
\(50 \mathrm{~g}\) of a substance is dissolved in \(1 \mathrm{~kg}\) of water at \(+90^{\circ} \mathrm{C}\). The temperature is reduced to \(+10^{\circ} \mathrm{C}\). The density is increased from 1.1 to \(1.15 \mathrm{~g} \mathrm{cc}^{-1}\). What is the \(\%\) change of molarity of the solution?
- A \(10\)
- B \(4.5\)
- C \(5\)
- D \(7.3\)
Answer & Solution
Correct Answer
(B) \(4.5\)
Step-by-step Solution
Detailed explanation
Molarity \(=\frac{\text { Weight dissolved }}{\text { Molar mass }} \times \frac{1000}{V(\mathrm{~mL})}\) and \(V=\frac{\text { Mass of solution }}{\text { Density }}\) Molarity (1) at \(90^{\circ} \mathrm{C}=\frac{50}{x} \times \frac{1000 \times 1.1}{1050}=\frac{52.38}{x}\)…
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