AP EAMCET · Maths · Indefinite Integration
If \(\int \log \left(a^2+x^2\right) d x=h(x)+C\), then \(\mathrm{h}(x)\) is equal to
- A \(x \log \left(a^2+x^2\right)+2 \tan ^{-1}\left(\frac{x}{a}\right)\)
- B \(x^2 \log \left(a^2+x^2\right)+x+a \tan ^{-1}\left(\frac{x}{a}\right)\)
- C \(x \log \left(a^2+x^2\right)-2 x+2 a \tan ^{-1}\left(\frac{x}{a}\right)\)
- D \(x^2 \log \left(a^2+x^2\right)+2 x-a^2 \tan ^{-1}\left(\frac{x}{a}\right)\)
Answer & Solution
Correct Answer
(C) \(x \log \left(a^2+x^2\right)-2 x+2 a \tan ^{-1}\left(\frac{x}{a}\right)\)
Step-by-step Solution
Detailed explanation
Let \(l=\int \log \left(a^2+x^2\right) d x\) By using method of integration by parts, we get \(=\log \left(a^2+x^2\right) \int d x-\int\left\{\frac{d\left(\log \left(a^2+x^2\right)\right.}{d x} \int d x\right\} d x+C\)…
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