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AP EAMCET · Maths · Probability

If \(\mathrm{A}\) and \(\mathrm{B}\) are two events of a random experiment such that \(P(A \cup B)=0.65\) and \(P(A \cap B)=0.15\), then \(\mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})=\)

  1. A \(0.5\)
  2. B \(1.0\)
  3. C \(1.2\)
  4. D \(0.8\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1.2\)

Step-by-step Solution

Detailed explanation

Since we know that \[ \begin{aligned} & P(A \cup B)=P(A)+P(B)-P(A \cap B) \\ & \Rightarrow \quad P(A)+P(B)=P(A \cup B)+P(A \cap B) \\ & \Rightarrow \quad P(A)+P(B)=0.65+0.15=0.8 \end{aligned} \] we also know that…