AP EAMCET · Maths · Probability
If \(\mathrm{A}\) and \(\mathrm{B}\) are two events of a random experiment such that \(P(A \cup B)=0.65\) and \(P(A \cap B)=0.15\), then \(\mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})=\)
- A \(0.5\)
- B \(1.0\)
- C \(1.2\)
- D \(0.8\)
Answer & Solution
Correct Answer
(C) \(1.2\)
Step-by-step Solution
Detailed explanation
Since we know that \[ \begin{aligned} & P(A \cup B)=P(A)+P(B)-P(A \cap B) \\ & \Rightarrow \quad P(A)+P(B)=P(A \cup B)+P(A \cap B) \\ & \Rightarrow \quad P(A)+P(B)=0.65+0.15=0.8 \end{aligned} \] we also know that…
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