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AP EAMCET · Maths · Probability

If \(A\) and \(B\) are events of a random experiment with \(P(A)\) \(=0.5, \mathrm{P}(\mathrm{B})=0.4\) and \(\mathrm{P}(\mathrm{A} \cap \mathrm{B})=0.3\), then the probability that neither A nor B occurs is

  1. A \(0.04\)
  2. B \(0.4\)
  3. C \(0.8\)
  4. D \(0.2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.4\)

Step-by-step Solution

Detailed explanation

We know, \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\) \(\Rightarrow P(A \cup B)=0.5+0.4-0.3=0.6\) So probability neither A nor \(B=1-0.6=0.4\)