AP EAMCET · Maths · Probability
If \(A\) and \(B\) are events of a random experiment with \(P(A)\) \(=0.5, \mathrm{P}(\mathrm{B})=0.4\) and \(\mathrm{P}(\mathrm{A} \cap \mathrm{B})=0.3\), then the probability that neither A nor B occurs is
- A \(0.04\)
- B \(0.4\)
- C \(0.8\)
- D \(0.2\)
Answer & Solution
Correct Answer
(B) \(0.4\)
Step-by-step Solution
Detailed explanation
We know, \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\) \(\Rightarrow P(A \cup B)=0.5+0.4-0.3=0.6\) So probability neither A nor \(B=1-0.6=0.4\)
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