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AP EAMCET · Maths · Sequences and Series

If \(a^2 x^4+b^2 y^4=c^6\) then maximum value of \(x y=\)

  1. A \(\frac{c^3}{2 a b}\)
  2. B \(\frac{c^3}{\sqrt{2 a b}}\)
  3. C \(\frac{c^3}{a b}\)
  4. D \(\frac{c^3}{\sqrt{a b}}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{c^3}{\sqrt{2 a b}}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & a^2 x^4+b^2 y^4=c^6 \\ & \Rightarrow \frac{a^2 x^4+b^2 y^4}{2} \geq \sqrt{a^2 b^2 x^4 y^4} \Rightarrow \frac{c^6}{2} \geq a b x^2 y^2 \\ & \Rightarrow x^2 y^2 \leq \frac{c^6}{2 a b} \Rightarrow x y \leq \frac{c^3}{\sqrt{2 a b}} .\end{aligned}\)