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AP EAMCET · Maths · Limits

If α=limx0x·2x-x1-cosx and β=limx0x·2x-x1+x2-1-x2, then

  1. A α=5β
  2. B α=2β
  3. C β=2α2
  4. D β=16α
Verified Solution

Answer & Solution

Correct Answer

(B) α=2β

Step-by-step Solution

Detailed explanation

It is given that, α=limx→0x·2x-x1-cosx Apply L hospital rule, a=limx→02x+x·2xlog2-1sinx Again, apply L hospital rule, α=limx→02xlog2+2xlog2+x·2x(log2)2cosx α=log2+log2 α=2log2 …i Now…