AP EAMCET · Maths · Pair of Lines
If \(2 x^2+3 x y-2 y^2-5 x+2\) fy \(-3=0\) represents a pair of straight lines, then one of the possible values of \(f\) is
- A \(-\frac{25}{2}\)
- B \(25\)
- C \(-5\)
- D \(\frac{5}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{2}\)
Step-by-step Solution
Detailed explanation
\(a=2, b=-2, c=-3, h=\frac{3}{2}, g=-\frac{5}{2}, f=f\) \(abc+2fgh-af^2-bg^2-ch^2=0\) \((2)(-2)(-3)+2(f)(-\frac{5}{2})(\frac{3}{2})-(2)(f)^2-(-2)(-\frac{5}{2})^2-(-3)(\frac{3}{2})^2=0\) \(12-\frac{15}{2}f-2f^2+\frac{25}{2}+\frac{27}{4}=0\) \(-8f^2-30f+125=0\)…
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