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AP EAMCET · Maths · Complex Number

If \((2+i)\) is a root of the equation \(x^3-5 x^2+9 x-5=0\), then the other roots are

  1. A 1 and \((2-i)\)
  2. B -1 and \((3+i)\)
  3. C 0 and 1
  4. D -1 and \((-2+i)\)
Verified Solution

Answer & Solution

Correct Answer

(A) 1 and \((2-i)\)

Step-by-step Solution

Detailed explanation

It is given that \(2+i\) is the root of the equation \(x^3-5 x^2+9 x-5=0\), so another non-real complex root will be \(2-i\). Now, let the third root is \(\alpha\), so by product of roots, we have \((2+i)(2-i) \alpha=5 \Rightarrow \alpha=1\) Hence, option (a) is correct.