AP EAMCET · Maths · Complex Number
If \((2+i)\) is a root of the equation \(x^3-5 x^2+9 x-5=0\), then the other roots are
- A 1 and \((2-i)\)
- B -1 and \((3+i)\)
- C 0 and 1
- D -1 and \((-2+i)\)
Answer & Solution
Correct Answer
(A) 1 and \((2-i)\)
Step-by-step Solution
Detailed explanation
It is given that \(2+i\) is the root of the equation \(x^3-5 x^2+9 x-5=0\), so another non-real complex root will be \(2-i\). Now, let the third root is \(\alpha\), so by product of roots, we have \((2+i)(2-i) \alpha=5 \Rightarrow \alpha=1\) Hence, option (a) is correct.
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