AP EAMCET · Maths · Basic of Mathematics
\(\frac{x-1}{3 x+4} < \frac{x-3}{3 x-2}\) holds, for all \(\mathrm{x}\) in the interval
- A \(\left(\frac{-4}{3}, \frac{2}{3}\right)\)
- B \(\left(-\infty, \frac{-5}{4}\right)\)
- C \((-\infty)\)
- D \(\left(-\infty, \frac{-5}{4}\right) \cup\left(\frac{3}{4},-\infty\right)\)
Answer & Solution
Correct Answer
(A) \(\left(\frac{-4}{3}, \frac{2}{3}\right)\)
Step-by-step Solution
Detailed explanation
Given that, \(\frac{x-1}{3 x+4}-\frac{x-3}{3 x-2} \(\therefore \quad x\) lies in the interval \(\left(-\frac{4}{3}, \frac{2}{3}\right)\).
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