AP EAMCET · Maths · Basic of Mathematics
If \(\frac{1}{x^4+x^2+1}=\frac{A x+B}{x^2+x+1}+\frac{C x+D}{x^2-x+1}\), then \(C+D\) is equal to
- A \(-1\)
- B \(1\)
- C \(2\)
- D \(0\)
Answer & Solution
Correct Answer
(D) \(0\)
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