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AP EAMCET · Maths · Complex Number

If \(1, \omega, \omega^2\) are the cube roots of unity, then \(\frac{1}{1+2 \omega}+\frac{1}{2+\omega}-\frac{1}{1+\omega}=\)

  1. A 1
  2. B \(\omega\)
  3. C \(\omega^2\)
  4. D 0
Verified Solution

Answer & Solution

Correct Answer

(D) 0

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Given, } \frac{1}{1+2 \omega}+\frac{1}{2+\omega}-\frac{1}{1+\omega} \\ & =\frac{2+\omega+1+2 \omega}{(1+2 \omega)(2+\omega)}-\frac{1}{(1+\omega)} \\ & =\frac{3+3 \omega}{(1+2 \omega)(2+\omega)}-\frac{1}{(1+\omega)} \\ & =\frac{(3+3…