AP EAMCET · Maths · Complex Number
If \(1, \omega, \omega^2\) are the cube roots of unity, then \(\frac{1}{1+2 \omega}+\frac{1}{2+\omega}-\frac{1}{1+\omega}=\)
- A 1
- B \(\omega\)
- C \(\omega^2\)
- D 0
Answer & Solution
Correct Answer
(D) 0
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given, } \frac{1}{1+2 \omega}+\frac{1}{2+\omega}-\frac{1}{1+\omega} \\ & =\frac{2+\omega+1+2 \omega}{(1+2 \omega)(2+\omega)}-\frac{1}{(1+\omega)} \\ & =\frac{3+3 \omega}{(1+2 \omega)(2+\omega)}-\frac{1}{(1+\omega)} \\ & =\frac{(3+3…
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