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AP EAMCET · Maths · Probability

For three events A, B and C of a sample space, P(exactly one of A or B occurs)= \(\mathrm{P}(\) exactly one of B or C occurs \()=\mathrm{P}(\) exactly one of C or A occurs \()=\frac{1}{4}\). If probability of all the three events occuring simultaneously is \(\frac{1}{16}\), then the probability that atleast one of the events occur is

  1. A \(\frac{3}{16}\)
  2. B \(\frac{5}{16}\)
  3. C \(\frac{7}{16}\)
  4. D \(\frac{7}{32}\)
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Answer & Solution

Correct Answer

(C) \(\frac{7}{16}\)

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Detailed explanation

\( \mathrm{P}(\text{exactly one of X or Y occurs}) = \mathrm{P}(\mathrm{X}) + \mathrm{P}(\mathrm{Y}) - 2\mathrm{P}(\mathrm{X} \cap \mathrm{Y}) \)…
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