AP EAMCET · Maths · Trigonometric Ratios & Identities
\(\sin \frac{\pi}{12} \sin \frac{2 \pi}{12} \sin \frac{3 \pi}{12} \sin \frac{4 \pi}{12} \sin \frac{5 \pi}{12} \sin \frac{6 \pi}{12}=\)
- A \(\frac{\sqrt{3}}{16 \sqrt{2}}\)
- B \(\frac{\sqrt{3}}{8 \sqrt{2}}\)
- C \(\frac{1}{32}\)
- D \(\frac{1}{16}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{3}}{16 \sqrt{2}}\)
Step-by-step Solution
Detailed explanation
\(P = \sin \frac{\pi}{12} \sin \frac{2 \pi}{12} \sin \frac{3 \pi}{12} \sin \frac{4 \pi}{12} \sin \frac{5 \pi}{12} \sin \frac{6 \pi}{12}\) \(P = \sin \frac{\pi}{12} \sin \frac{\pi}{6} \sin \frac{\pi}{4} \sin \frac{\pi}{3} \sin \frac{5 \pi}{12} \sin \frac{\pi}{2}\)…
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