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AP EAMCET · Maths · Permutation Combination

For which value of nN, n! has 13 trailing zeros?

  1. A 51
  2. B 54
  3. C 57
  4. D 60
Verified Solution

Answer & Solution

Correct Answer

(C) 57

Step-by-step Solution

Detailed explanation

We know in n! exponent of 5 is always less than or equal to exponent of 2 Hence, exponent of 5 is equal to the number of trailing zeroes We know, exponent of 5 in n! is given as ⇒13=n5+n52+n53+... Using n=57 from the options, we get =575+5725+57125 =11+2+0 ... So, in…