AP EAMCET · Maths · Probability
A bag contains 2 white, 3 green and 5 red balls. If three balls are drawn one after the other without replacement, then the probability that the last ball drawn was red is
- A \(\frac{2}{3}\)
- B \(\frac{3}{4}\)
- C \(\frac{5}{9}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Since, A bag has 2 white, 3 green and 5 red balls. Now, number of ways of choosing 3 ball such that last ball is \(\mathrm{red}=8 \times 9 \times 5\) So, required probability \(=\frac{8 \times 9 \times 5}{10 \times 9 \times 8}=\frac{1}{2}\).
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