AP EAMCET · Maths · Circle
Find the value of \(m+n\), if the circumference of the circle \(x^2+y^2+8 x+8 y-m=0\) is bisected by the circle \(x^2+y^2-2 x+4 y+n=0\).
- A -56
- B 56
- C 50
- D -34
Answer & Solution
Correct Answer
(A) -56
Step-by-step Solution
Detailed explanation
Let \(S_1 \equiv x^2+y^2+8 x+8 y-m=0\) \(S_2=x^2+y^2-2 x+4 y+n=0\) Equation of common chord \(\begin{aligned} \Rightarrow & & S_1-S_2 & =0 \\ \Rightarrow & & 10 x+4 y-(m+n) & =0 \\ \Rightarrow & & 10 x+4 y & =(m+n) \end{aligned}\) Centre of bisected circle is \((-4,-4)\) which…
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