AP EAMCET · Maths · Continuity and Differentiability
Consider the following functions
I) \(f(x)=\left\{\begin{array}{cc}\frac{1}{2}-x, & x < \frac{1}{2} \\ \left(\frac{1}{2}-x\right)^2, & x \geq \frac{1}{2}\end{array}\right.\)
II) \(f(x)=|3 x-1|\)
III) \(f(x)=x|x|\)
IV) \(f(x)=|x|\)
Then on \([0,1]\) Lagrange's mean value theorem is applicable to the functions
- A III, IV
- B II, III
- C I, III
- D II, IV
Answer & Solution
Correct Answer
(A) III, IV
Step-by-step Solution
Detailed explanation
I) For \(x \frac{1}{2}\), \(f'(x) = 2x-1\). \(f'(\frac{1}{2}^-) = -1\), \(f'(\frac{1}{2}^+) = 2(\frac{1}{2})-1 = 0\). Not differentiable at \(x=\frac{1}{2}\). Not applicable. II) For \(x \frac{1}{3}\), \(f'(x) = 3\). \(f'(\frac{1}{3}^-) = -3\), \(f'(\frac{1}{3}^+) = 3\). Not…
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