AP EAMCET · Maths · Trigonometric Ratios & Identities
Assertion (A):If \(\mathrm{A}=10^{\circ}, \mathrm{B}=16^{\circ}, \mathrm{C}=19^{\circ}\), then \(\tan 2 \mathrm{~A}\) \(\tan 2 \mathrm{~B}+\tan 2 \mathrm{~B} \tan 2 \mathrm{C}+\tan 2 \mathrm{C} \tan 2 \mathrm{~A}=1\).
Reason (R): If \(A+B+C=180^{\circ},=\cot \frac{A}{2} \cdot \cot \frac{B}{2} \cdot \cot \frac{C}{2}\) \(=\cot \frac{\mathrm{A}}{2} \cdot \cot \frac{\mathrm{~B}}{2} \cdot \cot \frac{\mathrm{C}}{2}\)
Which of the following is correct?
- A Both (A) and (R) are true and (R) is the correct explanation of (A)
- B Both (A) and (R) are true and (R) is NOT correct explanation of (A)
- C (A) is true, (R) is false
- D (A) is false, (R) is true
Answer & Solution
Correct Answer
(A) Both (A) and (R) are true and (R) is the correct explanation of (A)
Step-by-step Solution
Detailed explanation
Given that \(A=10^{\circ}, B=16^{\circ}\) and \(C=19^{\circ}\) \(A+B+C=45^{\circ} \Rightarrow 2 A+2 B+2 C=90^{\circ}\)...(i) We know that, \(\tan (2 A+2 B+2 C)\)…
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